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#1 Posted : Wednesday, September 3, 2008 5:57:02 PM(UTC)
יגאל

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I wanted to hear opinions from a used or heard about the shoe if it matches the tracks with the weight on your back.
For a total of six months.
The north face also bought a k blaze
Gregory baltoro 70L
Thanks in advance!! :)
Sponsor
User  
#2 Posted : Wednesday, September 3, 2008 6:21:29 PM(UTC)
זמי1

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Israel

Can't remember which track shoes, Gore-Tex, and they hope this is what you need in the Israel National Trail (INT) there is no need for such.

About the weight on your back, remember this formula:

The selection is function of the foot pad width/height of the Arch of the foot//weight/weight casing your Prime/ankles/character strengths.

I for instance going today with low Gore-Tex shoes vasek and want free.

Time (shkrsvali were weak.) I only use rigid shoe and higher.

זמי1 39694.6419675926
User  
#3 Posted : Wednesday, September 3, 2008 9:18:15 PM(UTC)
YANKALE17

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Israel

I read about the complexity of choosing shoes. Schr?dinger equations were easier to resolve.
User  
#4 Posted : Thursday, September 4, 2008 12:57:52 PM(UTC)
זמי1

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And here the solution of Schr?dinger equation:

Solving the equation

The method to solve themadhhab (partial differential equations) of the Schr?dinger equation is by separation of variables. Guess the solution


 \psi t,\vecr = e^-iEt/\hbar \Psi \vecr

Then for ? are given independent Schr?dinger equation depends on:




 E \Psi \vecr = \frac- \hbar ^22m \nabla ^2 \Psi \vecr + V\vecr \Psi \vecr

This is comparing values down which can be solved using Sturm liouville theory. In fact, we seek functions ?n so that


 \ H \Psi_n = E_n \Psi_n,

IE: the operator Hamiltonian cycle them simply returns double theenergy . These energies (which are the self-portraits of the gauge) called "the self" and their respective functions called "autologous" modes. Wake you self drive States tonormalize, meaning to multiply by a factor that scalar  \lang \Psi_n  \Psi_n \rang = 1 . The normalization requirement stems from the hpiroshthe probability of quantum mechanics.

Because it's a linearequation, the general solution can be viewed asquantum superposition of States, namely:






 \psi t,\vecr = \sum_n A_n \Psi_n \vecr e^-\fraci\hbarE_n t

Because H is an operator is self-adjoint, promised fromHilbert's theorem that there exists a basis of self ortonormalimconditions, IE \lang \psi_n  \psi_m \rang = \delta_n,m . Therefore, you can view all wave function in theHilbert space of the problem as a sum (specifically infinite series) of individual situations (such development drive read Fourier development).

The development front An can be determined by knowing the initial wave function (i.e. \ \psi 0,\vecr , identically completely done for Fourier series , also normalize the wave function such that: \lang \psi  \psi \rang = 1

Amtrak  
#5 Posted : Thursday, September 4, 2008 1:08:43 PM(UTC)
Amtrak

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Israel

Should urgent administration, to take immediately all the obscene talk forum!

Heads will roll!

User  
#6 Posted : Thursday, September 4, 2008 3:16:50 PM(UTC)
זמי1

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Israel

Make sure head.

Cut down on his knees.

Skin

Crash on Eisenhower

Look at his eyes begging:

Please, please

Don't stop.

Amtrak  
#7 Posted : Thursday, September 4, 2008 4:35:10 PM(UTC)
Amtrak

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Man
Israel

That painful?
oded  
#8 Posted : Saturday, September 6, 2008 10:00:55 PM(UTC)
oded

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In December I did the test on the ... Schr?dinger reviewed multiple times but always good to read again.
The next step, it's available to solve non-linear Schr?dinger equation that depends on time.
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